A stock solution of HNO 3 is prepared and found to contain 14.9 M of HNO 3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is ________ M.
Stock solution concentration (S1)=14.9M
Stock solution volume (V1)=25ml
Diluted solution volume (v2)=0.5L
=.5×1000ml
=500ml
so S2=?
we use the formula, V1S1=V2S2
S2=(V1S1)/V2
= (25×14.9)/500
=0.745M
the concentration of the diluted solution is 0.745 M.
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