Calculate the pH of 0.012 g of HNO3 in 500 ml solution?

Q.Calculate the pH of 0.012 g of HNO3 in 500 ml solution?  

Molar mass of HNO3 = 63.01 g

We know, pH=-log [H+]

[H+]= Molar Concen tration of H+ i on.

when,
63.01g of HNO2 dissolvesin 1000mL Molarity = 1m

now when 0.012g HHO3 is added in 500 ml then molarity = 9.5X10 5

:· [H+] = 9.5x10^-5 M

PH = - log (9:5 x10^-5)

we get pH= 4.02

PH of the solution is 4.02.

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